Relation between (COP)refrigerator and (COP)HP
- Admin
- Aug 28, 2020
- 1 min read
Let us consider a reverse device which may work as refrigerator as well as heat pump if both the devices are taking and rejecting some amount of heat.
(COP) Rf = Desired effect /input = Q₂ /(Q₁ - Q₂) -----(1)
(COP) HP = Desired effect /input = Q₁ /(Q₁ - Q₂) -----(2)
Subtracting (1) from (2)
(COP) HP - (COP) Rf = [Q₁ /(Q₁ - Q₂)] – [Q₂ /(Q₁ - Q₂)]
(COP) HP - (COP) Rf = (Q₁ - Q₂) / (Q₁ - Q₂)
(COP) HP - (COP) Rf = 1
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